MySQL 如何使用LIKE从第一个表创建新表
首先,让我们创建一个表 –
mysql> create table DemoTable1
(
EmployeeId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
EmployeeName varchar(50)
);
Query OK, 0 rows affected (0.48 sec)
Mysql
使用插入语句在表中插入一些记录 –
mysql> insert into DemoTable1(EmployeeName) values('Tom');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable1(EmployeeName) values('Mike');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable1(EmployeeName) values('Emma');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable1(EmployeeName) values('Sam');
Query OK, 1 row affected (0.10 sec)
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使用select语句显示表中的所有记录:
mysql> select *from DemoTable1;
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输出如下:
+------------+--------------+
| EmployeeId | EmployeeName |
+------------+--------------+
| 1 | Tom |
| 2 | Mike |
| 3 | Emma |
| 4 | Sam |
+------------+--------------+
4 rows in set (0.00 sec)
Mysql
以下是使用MySQL中的LIKE从另一个表创建新表的查询:
mysql> create table DemoTable2 LIKE DemoTable1;
Query OK, 0 rows affected (0.55 sec)
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让我们检查表的描述:
mysql> desc DemoTable2;
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输出如下:
+--------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+-------------+------+-----+---------+----------------+
| EmployeeId | int(11) | NO | PRI | NULL | auto_increment |
| EmployeeName | varchar(50) | YES | | NULL | |
+--------------+-------------+------+-----+---------+----------------+
2 rows in set (0.00 sec)
Mysql
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