MySQL 如何在查询中比较年、月和日，并显示匹配的记录

可以使用DATE()来实现。首先创建一个表 –

mysql> create table DemoTable864(DueDateTime timestamp);
Query OK, 0 rows affected (0.56 sec)

使用插入命令向表中插入一些记录 –

mysql> insert into DemoTable864 values('2019-01-10 12 −34 −55');
Query OK, 1 row affected (0.26 sec)
mysql> insert into DemoTable864 values('2016-12-11 11 −12 −00');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable864 values('2015-04-01 10 −00 −00');
Query OK, 1 row affected (0.28 sec)
mysql> insert into DemoTable864 values('2017-05-20 04 −40 −10');
Query OK, 1 row affected (0.17 sec)

使用select语句显示表中所有记录 –

mysql> select *from DemoTable864;

这将产生以下输出 –

+---------------------+
| DueDateTime         |
+---------------------+
|2019-01-10 12 −34 −55|
|2016-12-11 11 −12 −00|
|2015-04-01 10 −00 −00|
|2017-05-20 04 −40 −10|
+---------------------+
4 rows in set (0.00 sec)

以下是比较年、月和日的查询 –

mysql> select *from DemoTable864 where date(DueDateTime)='2015-04-01';

这将产生以下输出 –

+-----------------------+
| DueDateTime           |
+-----------------------+
| 2015-04-01 10 −00 −00 |
+-----------------------+
1 row in set (0.04 sec)

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