MySQL 如何使用WHERE子句中的循环来仅显示交替ID记录？

使用MySQL IN()获得类似的结果。首先创建一个表 –

mysql> create table DemoTable
(
ClientId int,
ClientName varchar(100),
ClientAge int
);
Query OK, 0 rows affected (0.70 sec)

使用insert命令在表中插入一些记录 –

mysql> insert into DemoTable values(100,'Chris',34);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable values(101,'Robert',31);
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable values(103,'David',33);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable values(104,'Mike',45);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable values(105,'Sam',39);
Query OK, 1 row affected (0.09 sec)

使用select语句显示表中的所有记录 –

mysql> select *from DemoTable;

这将生成以下输出 –

+----------+------------+-----------+
| ClientId | ClientName | ClientAge |
+----------+------------+-----------+
|      100 | Chris      |        34 |
|      101 | Robert     |        31 |
|      103 | David      |        33 |
|      104 | Mike       |        45 |
|      105 | Sam        |        39 |
+----------+------------+-----------+
5 rows in set (0.00 sec)

以下是使用MySQL IN()获得类似循环的查询 –

mysql> select ClientId,ClientName,ClientAge from DemoTable
where ClientId IN(101,103,105);

这将生成以下输出 –

+----------+------------+-----------+
| ClientId | ClientName | ClientAge |
+----------+------------+-----------+
|      101 | Robert     |        31 |
|      103 | David      |        33 |
|      105 | Sam        |        39 |
+----------+------------+-----------+
3 rows in set (0.00 sec)

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