Java AbstractSequentialList的get()方法及示例

Java AbstractSequentialList的get()方法及示例

AbstractSequentialList的get()方法用于从AbstractSequentialList的特定索引处获取或检索一个元素。

语法

AbstractSequentialList.get(int index)

参数: 参数index是整数数据类型,指定了要从AbstractSequentialList中获取的元素的位置或索引。

返回值: 该方法返回由参数index指定的位置上的元素。

下面的程序说明了Java.util.AbstractSequentialList.get()方法。

例1 :

// Java code to illustrate get() method
  
import java.util.*;
import java.util.AbstractSequentialList;
  
public class AbstractSequentialListDemo {
    public static void main(String args[])
    {
  
        // Creating an empty AbstractSequentialList
        AbstractSequentialList<String>
            absqlist = new LinkedList<String>();
  
        // Use add() method to add elements
        absqlist.add("Geeks");
        absqlist.add("for");
        absqlist.add("Geeks");
        absqlist.add("10");
        absqlist.add("20");
  
        // Displaying the list
        System.out.println("AbstractSequentialList:"
                           + absqlist);
  
        // Fetching the specific element from the list
        System.out.println("The element is: "
                           + absqlist.get(2));
    }
}

输出。

AbstractSequentialList:[Geeks, for, Geeks, 10, 20]
The element is: Geeks

例2 :

// Java code to illustrate get() method
  
import java.util.*;
import java.util.AbstractSequentialList;
  
public class AbstractSequentialListDemo {
    public static void main(String args[])
    {
  
        // Creating an empty AbstractSequentialList
        AbstractSequentialList<Integer>
            absqlist = new LinkedList<Integer>();
  
        // Use add() method to add elements
        absqlist.add(1);
        absqlist.add(2);
        absqlist.add(3);
        absqlist.add(4);
        absqlist.add(5);
  
        // Displaying the list
        System.out.println("AbstractSequentialList:"
                           + absqlist);
  
        // Fetching the specific element from the list
        System.out.println("The element is: "
                           + absqlist.get(4));
    }
}

输出。

AbstractSequentialList:[1, 2, 3, 4, 5]
The element is: 5

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