Java AbstractList get() 方法及示例
get() 方法属于 java.util.AbstractList 类,用于返回列表中指定位置的元素。
语法:
public abstract E get(int index)
参数: 此方法以元素的索引为参数,该元素将被返回。
返回值: 此方法返回列表中指定位置的元素。
异常: 如果索引超出范围 (index = size()),则此方法将引发 IndexOutOfBoundsException 。
下面是说明get()方法的示例。
示例1:
// Java program to demonstrate
// get() method
// for Integer value
import java.util.*;
public class GFG1 {
public static void main(String[] argv) throws Exception {
try {
// Creating object of AbstractList<Integer>
AbstractList<Integer> arrlist1 = new ArrayList<Integer>();
// Populating arrlist1
arrlist1.add(10);
arrlist1.add(20);
arrlist1.add(30);
arrlist1.add(40);
arrlist1.add(50);
// print arrlist1
System.out.println("ArrayListlist : " + arrlist1);
// getting the value at the index 3 using get() method
int value = arrlist1.get(3);
// print the value
System.out.println("Element at index 3 : " + value);
}
catch (IndexOutOfBoundsException e) {
System.out.println("Exception thrown : " + e);
}
}
}
ArrayListlist : [10, 20, 30, 40, 50]
Element at index 3 : 40
示例2:
// Java program to demonstrate
// get() method
// for IndexOutOfBoundsException
import java.util.*;
public class GFG1 {
public static void main(String[] argv) throws Exception {
try {
// Creating object of AbstractList<Integer>
AbstractList<Integer> arrlist1 = new ArrayList<Integer>();
// Populating arrlist1
arrlist1.add(10);
arrlist1.add(20);
arrlist1.add(30);
arrlist1.add(40);
arrlist1.add(50);
// print arrlist1
System.out.println("ArrayListlist : " + arrlist1);
// getting the value at the index 7 using get() method
System.out.println("\nTrying to get " + "the element from out" + " of range index ");
int value = arrlist1.get(7);
// print the value
System.out.println("Element at index 7 : " + value);
}
catch (IndexOutOfBoundsException e) {
System.out.println("Exception thrown : " + e);
}
}
}
ArrayListlist : [10, 20, 30, 40, 50]
Trying to get the element from out of range index
Exception thrown : java.lang.IndexOutOfBoundsException: Index: 7, Size: 5